Bilunabirotunda (EntityTopic, 14)

From Hi.gher. Space

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| image=<[#embed [hash E8W2T39SHBA6TBWV9MR9AY87GA] [width 160]]>
| elements=14, 26, 14
| elements=14, 26, 14
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| sym=[[Biprismatic symmetry|D<sub>2h</sub>]]
| genus=0
| genus=0
| extra={{STS Polytope
| extra={{STS Polytope
| flayout={{FLD|a2tr|ti|asrtm|ditm|aqtm|editm|atlsl|cr}}
| flayout={{FLD|a2tr|ti|asrtm|ditm|aqtm|editm|atlsl|cr}}
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| bowers=Bilbiro
}}}}
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The '''bilunabirotunda''' is the 91st [[Johnson solid]], J91. It suddenly became important when the [[castellated rhodoperihedral prism]] was discovered.
The '''bilunabirotunda''' is the 91st [[Johnson solid]], J91. It suddenly became important when the [[castellated rhodoperihedral prism]] was discovered.
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== Coordinates ==
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The following coordinates give an origin-centered bilunabirotunda with edge length 2:
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:<±1, 0, ±φ<sup>2</sup>>
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:<±φ, ±1, ±1>
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:<0, ±φ, 0>
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where φ=(1+√5)/2 is the Golden Ratio.
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== Construction from icosahedron ==
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The bilunabirotunda can be constructed from an icosahedron, as follows:
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Firstly, write the icosahedron in [2,2,2]-symmetry:
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    x2o2f
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    f2x2o
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    o2f2x
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Then, apply a caleido-faceting to the last node:
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    x2o2f -> x2o2f
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    f2x2o -> f2x2o
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    o2f2x -> o2f2(-x)
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Finally, apply a Stott-expansion to the last node:
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    x2o2f    -> x2o2F
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    f2x2o    -> f2x2x
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    o2f2(-x) -> o2f2o
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The result is J91, written in [2,2,2]-symmetry: xfo2oxf2Fxo&#zx.
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You can compare this representation with the coordinates as given above.
== Equations ==
== Equations ==
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surface area = (2 + 2√3 + √(25+10√5)) {{DotHV}}<br>
surface area = (2 + 2√3 + √(25+10√5)) {{DotHV}}<br>
volume = {{Over|1|6}} &middot; (4φ<sup>2</sup> + 5φ) {{DotHV|3}}</blockquote>
volume = {{Over|1|6}} &middot; (4φ<sup>2</sup> + 5φ) {{DotHV|3}}</blockquote>
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<[#polytope [id 66]]>
{{Trishapes}}
{{Trishapes}}

Latest revision as of 10:38, 2 January 2018

The bilunabirotunda is the 91st Johnson solid, J91. It suddenly became important when the castellated rhodoperihedral prism was discovered.

Coordinates

The following coordinates give an origin-centered bilunabirotunda with edge length 2:

<±1, 0, ±φ2>
<±φ, ±1, ±1>
<0, ±φ, 0>

where φ=(1+√5)/2 is the Golden Ratio.

Construction from icosahedron

The bilunabirotunda can be constructed from an icosahedron, as follows:

Firstly, write the icosahedron in [2,2,2]-symmetry:

   x2o2f
   f2x2o
   o2f2x

Then, apply a caleido-faceting to the last node:

   x2o2f -> x2o2f
   f2x2o -> f2x2o
   o2f2x -> o2f2(-x)

Finally, apply a Stott-expansion to the last node:

   x2o2f    -> x2o2F
   f2x2o    -> f2x2x
   o2f2(-x) -> o2f2o

The result is J91, written in [2,2,2]-symmetry: xfo2oxf2Fxo&#zx.

You can compare this representation with the coordinates as given above.

Equations

  • The hypervolumes of a bilunabirotunda with side length l are given by:
total edge length = 26l
surface area = (2 + 2√3 + √(25+10√5)) · l2
volume = 16 · (4φ2 + 5φ) · l3

Incidence matrix

Dual: J91 dual

#TXIDVaVbVcEaEbEcEdEe3a3b4a5aTypeName
0 Va = point ; cuboid corners
1 Vb = point ; crosses
2 Vc = point ; ends
3 Ea 200 = digon ; vertical cuboid
4 Eb 200 = digon ; horizontal cuboid
5 Ec 110 = digon ; cross-to-cuboid
6 Ed 101 = digon ; end-to-cuboid
7 Ee 002 = digon ; ends
8 3a 21010200 = triangle ; cross
9 3b 20101020 = triangle ; end
10 4a 40022000 = square ;
11 5a 21200221 = pentagon ;
12 C1a 824448824424 = bilunabirotunda ;

Usage as facets


Notable Trishapes
Regular: tetrahedroncubeoctahedrondodecahedronicosahedron
Direct truncates: tetrahedral truncatecubic truncateoctahedral truncatedodecahedral truncateicosahedral truncate
Mesotruncates: stauromesohedronstauroperihedronstauropantohedronrhodomesohedronrhodoperihedronrhodopantohedron
Snubs: snub staurohedronsnub rhodohedron
Curved: spheretoruscylinderconefrustumcrind