Theory and Experiment of Zero Speed Of Light

[VishnuXXX]

Visualization Experiment


Experiment - 1
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Imagine that We at Star Trex Space Ship to analyzing the Light Frame from SuperNova. Actually we are very near at the star that will ended it's life. When Supernova Begin, the Ship Move with 99,999999999% c speed, go away from star. The Supernova Explosion wil send its picture frames explosion (light) to all direction. At The Ship that leaving the supernova, you will see the Explosion Stopped, Speeding or Same speed?

If Stop or slowing:
The Stopping of Time is cause from the picture frame(light) speed is move to your eyes actualy near zero.
Actually in the Relativity Theory The Light always Do 300.000 km/s even you move near c speed.
In another Theory, you will see the supernova normally, like it happen. But The Time in your ship slower and you see slow motion or stopped Nova.

The Light Speed Not Change wether you move or not, so what about this question?

1. Are The visualization of supernova exactly stopped when you go near speed of light, cause by the slowing time or slowing material system (your bio body too) in our ship?

2. Are The visualization of supernova exactly stopped when you go near speed of light, cause by the slowing of Light(picture Frame) that Reaching our eyes?

3. If We Move with 99,99999% c speed to the Super Nova Explotion, Can we see the Supernova speeding Up?
If Speeding, so the light (picture frame) go quick to our eyes.
If Not, the light do the same speed.
If Slowing, thats mean the material system or time slower at the ship.
Another way, the speed of our eyes or matter received light is 300.000km/s.
If The Super Nova Speeding Up, so the Picture Frame (light) go to our eyes rapidly.


Experiment - 2
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Now We are at the Moving Star Trex Ship to reach Earth. The Track is like the Sun Light Track to Earth. The Ship Move at 99,99999999...% c speed.
When We exactly at the sun we will shoot 2 Super Light Laser Beam(hypotetical). This Laser is in c speed. One Laser(Laser 1) Shooted to Earth, and another Laser(laser 2) To the Opposite Direction. At The Sun We Make Laser Canon Station. SO At The SUN we Shoot The laser(laser 3) to The Earth too, Laser 4 to the Opposite direction.(They are all happen at same time)

Laser 1 = From The Star Trex Ship, that shoot to Earth
Laser 2 = From The Star Trex SHip, that shoot to opposite direction.
Laser 3 = From The Sun, That Shoot to Earth.
Laser 4 = From The Sun, That Shoot To opposite Direction.

In this Experiment, people will make conclusion like this:
1. The Laser From the Sun Reach Earth in 8.33 Minute, The Star Trex Ship Crush The Earth in 8.33 minute.
What About The Laser 1 From The Ship That Shoot to Earth?
If Laser 1 reach Earth in 8.33 minute too, so the laser 1 never leave the ship, and the laser move exactly near zero to the ship. Same like The Firts Experiment, when Supernova Slowed or Stopped. Whether the Beam neveer shooted or leaving the canon beam.
(I dont like To use Einstein Equation, that make me feel dizzy)

2. What About The Laser 2 and laser 4, that shooted to opposite direction?
The Laser Reach Another Earth Track at 8.33 minutes too?
In MOvie The Laser(light) From Star Trex Ship Engine Stopped(make laser tail), it must be wrong.

The Laser 1 never leave the Canon Beam, but in Einstein Equation and Theory, the light will leave the Beam Cannon at c speed, and the ship actually zero speed.
In Visulization, the Earth Destroyed By 2 laser and One Ship. And The Laser 1 move in 300.000km/s relative from sun, earth, and ship without leaving the Ship.

So The Baldy Captain will Write The Tips, that You will not USE Laser Beam Canon when You move over Mach 1(c speed) or you will crush your own beam.

[Aale de Winkel]

Your postings reads like your namesake's.

Intermixing warp-theory (imaginairy remblings of star-treck story makers) with Einsteintonian physics (real life theory) is a bad idea. Shooting lasers at warp greater then 1, leave the ship at warp 1? γ = 1 / sqrt(1-β[sup]2[/sup]) will be an imaginairy number (for β = v/c > 1), so one really enters the realm of imaginairy physics , Einsteintonian physics simply doesn't apply in the imaginary Star-Treck or let say Cochcranian Physics.

[VishnuXXX]

Calculus and Geometry that We USe in this Earth and your Equation have limited to make Equation.


Maybe another time, I give a Revolution in Calculus and another mathematics, and then we can make anti gravity and Big Bang in Tech.

Bye.

[Aale de Winkel]

This has nothing to do with our type of 'calculus', which has been around since the ancient greeks, aside from some enhanchements by Newton and various other, I dont think we change from our linear system 1,2,3,4,.... to quadratic 1,2,4,9,16,... or even eliptic (used by Maya, the metamorphic science officer on MoonBase alpha who could make head-calculations faster then a computer )

Existing theories certainly can be falsified at some point, making warp-speed travel possible. Uptill the I'm limited to Einsteintonian physics.
Cochranian physics simply will be ruled by some other set of formulae, this changes nothing in the type of calculus!

[shogunu]

man, vishnu, your english is horrible (i'm no native english speaker either, but damn, yours is just awful)
i'll think more about these questions in the morning, here are some quick answers:
the exploding supernova will appear exploding normally, since when travelling at 0.99c time actually dilates (inside the ship) and even if it would take, let's say 1sec for the whole explosion to develop and it would take 1year from the beginning of the explosion till the finish to reach our space ship, that 1year will actually pass in only 1 sec inside the star ship
the single difference will be that the light arriving from the star will be redish (tilted twards the lower part of the spectrum)
the same happens when approaching the exploding star at 0.99c
when travelling to earth at 0.99c and shooting a laser twards it:
the laser will shoot out from the star ship at c speed, from inside the ship it will look like the laser is moving at c speed since time on the ship has dilated, even more if the actual time for the laser to reach earth will be 8.33mins on the ship it will look as if it takes only seconds for the laser to reach earth

/edit: fixed the second answer, originally mistaken the time interval that would pass on the ship, thought it would take years, but actually on the ship it only takes seconds

[jinydu]

Actually, the supernova explosion will look dilated. Remember, from your frame of reference, your ship is stationary (hence time is normal) and the supernova is moving backwards at 99.999999999% the speed of light (hence time is dilated).

Also remember that according to Special Relativity, your reference frame is as valid as the supernova's reference frame. You have just as much right to say that time is dilated on the supernova, as an observer on the supernova has a right to say that time is dilated on your ship.

[Watters]

also the fact that the ship would proble have so mcuh figin mass due the the incridible speed on it that the Space Time around it would bend so thatyou would get alot of crazy messed up vision of the whole experiance

[RQ]

nausea too...