quickfur wrote:[...] Let's say we start with the CD diagram of some top cell, and make some changes to it (adding rings/removing rings). What are the conditions in which such ringings will admit CRF segmentotopes? I do not have proof, but I believe that the case of adding a single ring to the CD diagram can always be made CRF, regardless of dimension. By the same token, removing a ring should also be CRF-able. But the case of removing 1 ring and adding 1 ring on another node seems to be more complicated. As we see above, in 6D you can no longer do this with x4ooooo || o4oooox. In 4D, we already can't have o5ox || o5xo be made CRF, although o4ox || o4xo is still possible (I think!). And I think x5oo || o5xo is still possible, too.
So the question is, what are the conditions in which removing and adding a ringed node to the CD diagram of the top cell will produce a bottom cell that can form a unit lace prism (i.e. a CRF segmentotope)? It seems that the relative positions of the unringed/ringed nodes play an important role here -- I believe that x4ooooo || o4xoooo should still be CRF-able; I could be wrong, but if I'm right, then where is the "breaking point"? Can x4oooo || o4oxooo be CRF-able? What about x4oooo || o4ooxoo? Or x4oooo || o4oooxo?
[...]
This morning I decided to do a quick calculation to determine whether x4ooo... || o4xoo... will always be CRF-able. Turns out that this is only CRF-able up to 19 dimensions.
Proof. Given edge length 2, the coordinates of x4ooo... are apacs<1,1,1,1,...,1>, and the coordinates of o4xoo... are apacs<0,sqrt(2),sqrt(2),sqrt(2),...,sqrt(2)>. If we construct an n-dimensional segmentotope from these (n-1)-dimensional facets, then its coordinates will be <1,1,1,...,1,H> and <0,sqrt(2),sqrt(2),...,sqrt(2),0> for some H>0. Since the edge length is 2, the difference between these two vectors must have a magnitude equal to 2, since otherwise the result will not be CRF.
So, ||<1,1,1,...,H> - <0,sqrt(2),sqrt(2),...,0>||^2 < 2^2, which gives us: 1 + (n-2)(sqrt(2)-1)^2 + H^2 = 4. A little algebra gives us: H^2 = (9-4*sqrt(2)) + n(2*sqrt(2)-3). Since we require H>0, so we also have H^2>0, which means:
(9-4*sqrt(2)) + n(2*sqrt(2)-3) > 0
n(2*sqrt(2)-3) > -(9-4*sqrt(2))
Now, note that since 8 < 9, so 2*sqrt(2) < 3, and so 2*sqrt(2) - 3 < 0. So we have to invert the sense of the inequality when we divide by 2*sqrt(2)-3:
n < -(9-4*sqrt(2)) / (2*sqrt(2)-3)
A little more algebra gives:
n < 11 + 6*sqrt(2)
The RHS works out to be about 19.49, and therefore we conclude that n≤19. QED.
This is interesting, because it means that in 20D, n-cube || rectified n-cube cannot be CRF! However, n-cross || rectified n-cross is always CRF-able. Why? Because n-cross is o4oo...ox, which has coordinates <0,0,0,...,0,sqrt(2)> and rectified n-cross is o4o...oxo, which has coordinates <0,0,0,...0,sqrt(2),sqrt(2)>. Note that the number of non-zero elements is independent of dimension. So to construct the segmentotope, we simply append H to the n-cross's coordinates and 0 to the rectified n-cross's coordinates: <0,0,0,...0,sqrt(2),H> and <0,0,...0,sqrt(2),sqrt(2),0>, respectively. Then given the requirement that the difference between these two points must have magnitude 2, we get:
||<0,0,0,...0,sqrt(2),H> - <0,0,...sqrt(2),sqrt(2),0>||^2 = 2^2
2 + H^2 = 4
H^2 = 2
H = sqrt(2)
Since H is independent of dimension, the segmentotope exists in all dimensions ≥3.