by wendy » Fri Jan 30, 2009 9:52 am
The black hole is considerably smaller than the star that produced it.
Consider the sun. The diameter of the sun is roughly 864000 miles. At the surface, the force of gravity is small, that light freely escapes. Where the sun to collapse to a black hole or a neutron star, gravity would be unchanged, and the planets would still orbit it, providing they survive any event that accompanies the collapse (usually a super-nova, but the devil's in the details).
The schwarzchild radius of the sun is the diameter of the black hole: literally, the radius where the escape velocity is the speed of light. For the sun, this is roughly one mile. The actual mass of the sun in this radius is very tiny, about 1e-18 of the total solar mass, so light escapes even here.
When a star looses the outwards pressure that prevents it collapsing, then gravity takes over, and the star crumbles under its own weight. For stars less than 1.4 solar masses, the diameter is larger than the schwarzchild radius, the result is a neutron star. For larger stars, the gravity takes it past this point, eventually falling into an ever-denser state. A black hole forms.
Mass is indeed not lost, but what happens when a black hole or neutron star forms, is that there's a lot more space before the surface is met, or more accurately, there is more matter much closer to a point on the surface, and gravity is indeed more. In a super-massive star, the distances are much larger, and the escape velocity is much smaller.