papernuke wrote:
cos(X)
= adjacent / hypotenuse
(c = a/h...."cah")
-houserichichi
So that just means the the cosine of the angel X is the oppsotie end (a) divided by c?
and the same is for the sin(X) and tang(X)?
s = o/h...."soh")
- houserichichi
how can s=o/h equal "soh" isnt soh multiplication? or is that what the name/say it?
nono...cosine is adjacent over hypotenuse. If you are trying to find the cosine of the angle that exists at the connection of the Hypotenuse line and the Adjacent line (I called that <BAC or, later, X) then
cos(X) = adj / hyp = b / c
sin(X) = opp / hyp = a / c
tan(X) = opp / adj = a / b
I was taught soh, cah, toa only to remember which three letters go together...pronounce them "so, kah, and toe-ah", they don't mean actual multiplications.
soh -> s = o / h
cah -> c = a / h
toa -> t = o / a
The one VERY important fact to remember is that hypotenuse is always across from the right angle and that the line labeled "opposite" is the one that is across from the angle you are working with. In my example I used <BAC so the line across from that is line "a". If, instead, we wanted to find cos(Y) where Y is the angle <ABC then "opposite" would be line "b" and "adjacent" would be line "a"....do you see why? Hypotenuse stays the same because the right angle didn't move.
Read the other responses too, as there's a lot more to trig than just simple number crunching like I'm making it out to be.