whoa, D4.10 is awesome

it has patches of D4.8 and J92 rombochoron aswell
take a look at this projection:

the three bilbiro's that share a 3-diminished ike, have a (more or less) equal orientation as D4.8.1

it has, starting from the bottom and a face of the tetrahedron closest to the 4D viewpoint in D4.10
a tridiminished ike (check)
3 bilbiro's surrounding (check)
3 tets filling in the gaps (check displayed green in D4.10)
an ochtahedra on top of the trdim. ike (check)
three octahedra surrounding (check)
a pentagonal cupola (sort of check, it is part of the D4.11's cuboctahedra, which are diminished to show the J92's)
this made me think of three things:
(1)

these things are awesome
(2) this might be a sub-group, as these are probably all be derived from the same operation
(3) this part probably can be expanded in D4.8 aswell, since this patch is expanded both in D.4.11.1 and D4.4.1
P.S. @ quickfur. in your first description, you wrote

The green patches are the 8 axial tetrahedra, lying along the 4 coordinate axes of 4D space. The red, orange, and yellow show 6 of the J91's around the nearest tetrahedron to the 4D viewpoint. The cyan cells are octahedra surrounded by 4 other octahedra: these fill the space where previously the J92's were. These 8 octahedra lie on the vertices of an alternated tesseract. On the vertices of the other alternated tesseract, are 8 cuboctahedra, here outlined in blue edges. These fill the space of where previously there were octahedron + 3 octahedra combos interfacing with J92 cells from the far side -- since the J92 cells are no more, cuboctahedra now fill that space. So here you can see demitesseractic symmetry very clearly.
after some thought regarding the orientation of the bilbiroes, it occured to me that it'd make more sense that the
cuboctahedra are where the J92's were, and the cyan cells the octahedra in D4.10, but I can't figure out how this works in D4.11.1.