0/0

[RQ]

1/0=0/0

How many of you believe me? Nobody? Ok take a look at this:

0/0=0/0

1-1/0=0/0

[1/0]-[1/0]=0/0

[1/0][2/2]-[1/0]=0/0

[2/0]-[1/0]=0/0

1/0=0/0 QED

[houserichichi]

When you start dealing with division by zero you get nonsense answers...it's still an indeterminate form which is why things don't look right. When you multiply (1/0) by (2/2) you're just using the natural laws or arithmetic that we were taught in grade school to perform the operation...however, 2/0 has no meaning (nor 1/0) so the proof doesn't show anything...it shows a set of symbols are equal, not numbers.

[houserichichi]

(1) The simplest proof agains that is if 0/0=1 then

(2) [0/0]2=[1]2

(3) 0/0=2

(4) 1=2?

I figured it belonged here instead...I thought you were multiplying the left side by 2 and the right side by 2 on line (2)...because if that's the case your next line (3) requires that you divide by 2 on the left and divide by 1 on the right.

0/0 can be ANY number, depending on the situation...you just showed that 1=2 by assuming that 0/0=1 which is not a valid assumption. Had you assumed that it equal something else, you could have had a different result, so your proof shows nothing more than arithmetic done under a false assumption.

[jinydu]

Remember that dividing by zero allows you to prove statements that are obviously false. This is a classic:

Assume a = b
a^2 = ab
a^2 - b^2 = ab - b^2
(a+b)*(a-b) = b*(a-b)
a+b = b
a+a = a
2a = a
2 = 1