by wendy » Mon Feb 15, 2021 8:59 am
Laminatruncates.
In hyperbolic space, the polytope t{4,3,8} = x4x3o8o, has the same curvature as one of its faces {3,8}. This means that this cell can be used to reflect the truncated cubes, to fill all-space, by itself. The dual is of octagon-prisms, these being the opposite faces of the truncated cube, so is not uniform. The symmetry is crossed {4,3,8}'s, with sections {3,8} and {8,4}. 16 tC at a vertex.
A second uniform is made from the octahedral ball. The verf is oxqxo8ooooo&#qt. The polar caps belong to triangular prisms, the lattitudes above and below the equator belong to 16 cells, each x4o3x. The diagonals of this verf is an octagon-verf, and the 24 non-polar vertices fall into two CO of this size.
In H4, the octahedral family is represented by ~4,3,8,2~, the symmetry forms a hexagon group with the mirror running through the diagonal. Using standard node positions, we note 1 and 4 are a dual pair of octagonny ~4x3o8o2~, and of bioctagon-prisms, ~4o3o8x2x~, which forms the only uniform ME/MM pair that is not wythoffian. ¬4x3o8o2~ which is the runcinate, also exists, along with Klitzing's discovery of ~4x3x8o2~. It is not known whether #2, #6 or #7 exist,