Though I hadnt time yet verifying Wendys assertion. Is it really true?
wendy wrote:torus(torus(torus(w,x),y)z).
what does that mean? are the toruses in those coodinates?
|| : ((||)|) == (||)| : ((||)(||)) ??
That is, the process that turns a square into torus as process X. Does process X also turn a cylinder into a tiger?
((11)1) torus = circle # circle
((11)11) toracubinder = circle # sphere
((111)1) toraspherinder = sphere # circle
(((11)1)1) ditorus = (circle # circle) # circle
((11)(11)) tiger = (circle x circle) # circle
The 'tiger' is a "spherated bi-glomohedrix prism". A glomo-hedr-ix is a round-2d-cloth, that is, the surface of a 3d sphere. The bi- bit means there are two of them, perpendicular to each other. A prism here may be read as a cartesian product. Spheraation is a surface finish, like a paint job. Here, it replaces thin things like lines and points and 2d fabric with solid things. Because the prism here is only 2d in 4d, we replace each point on the surface with a circle orthogonal to the 2d surface. That's what you get by replacing each point with a sphere.
ICN5D wrote:I guess what I meant to say was that process X is "lathe then spherate". If lathing a square into a cylinder, then spherating into a torus is process X. Does lathing a cylinder into a duocylinder, then spherating into a "torus" create the tiger?
ICN5D wrote:I understand it now. Thank you very much for that Wendy. You have no idea how long I've been trying to figure out the tiger. It was the name spherated bi-glomohedric prism that really did it. I understand the duocylinder to be the bi-circular prism. The spheration process turns the circles into glomohedrices before the cartesian product is applied. And because the shape was spherated, this word has to be attached to the bi-glomohedric prism. Wonderful!
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